Physics, asked by garrausinngh, 9 months ago

Solve this no spam my H.W ​

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Answered by Anonymous
25

\displaystyle\large\underline{\sf\green{Solution -1:- }}

\;\;\underline{\textbf{\textsf{ Given   :-}}}

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\sf{P=2\times10^9\ N\,m^{-2}}

\sf{\rho=1.2\times10\ kg\,m^{-3}}

\sf{g=10\ m\,s^{-2}.}

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\;\;\underline{\textbf{\textsf{ To Find    :-}}}

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• Height of the liquid column

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\;\;\underline{\textbf{\textsf{ Solution  :-}}}

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\underline{\:\textsf{ As we know that :}}⠀⠀⠀⠀⠀

\sf{ \dashrightarrow  P=\rho gh}

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\underline{\:\textsf{ Now, put the given values in the formula   :}}⠀⠀

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\sf{\dashrightarrow h=\dfrac{P}{\rho g}}

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\sf{ \dashrightarrow h=\dfrac{2\times10^9}{1.2\times10\times10}\ m}

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\bf{\dashrightarrow \underline{ \: \underline{ \green{ \: h =   1.67\times10^7 m\: }} \: }}

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⠀⠀⠀⠀⠀\displaystyle\large\underline{\sf\green{Solution -2:- }}⠀⠀

\;\;\underline{\textbf{\textsf{ Given   :-}}}

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\sf{m=3000\ kg}

\sf{A=425\times10^{-4}\ m^2}

\sf{g=10\ m\,s^{-2}.}

\;\;\underline{\textbf{\textsf{ To Find    :-}}}

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• Maximum pressure

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\;\;\underline{\textbf{\textsf{ Solution    :-}}}

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\underline{\:\textsf{ As we know the formula  :}}⠀⠀⠀⠀⠀

\sf{\dashrightarrow  P=\dfrac{F}{A}}

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\underline{\:\textsf{ Putting the values  :}}

\sf{\dashrightarrow  P=\dfrac{mg}{A}}

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\sf{ \dashrightarrow P=\dfrac{3000\times10}{425\times10^{-4}}\ N\,m^{-2}}

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\bf{ \dashrightarrow  \underline{ \: \underline{ \green{ \: P=   7.06\times10^5 m\: }} \: }}

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Answered by cn592120
1

Answer:

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