solve this numerical
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as T(timeperiod) = 2π √(l/g)
let g= 9.8 ms^(-2)
and T on this planet will be
T = 2π √(l/g)
let g' = 4.36 ms^(-2)
now T : T' is
√(g') : √(g)
√(4.36) : √(9.8)
2.088 : 3.13
0.667 : 1
let g= 9.8 ms^(-2)
and T on this planet will be
T = 2π √(l/g)
let g' = 4.36 ms^(-2)
now T : T' is
√(g') : √(g)
√(4.36) : √(9.8)
2.088 : 3.13
0.667 : 1
gopichandra:
but why we have underroot on g
as in formula we have under root on g
so while taking ratio all others get canceled out and only underroot g are left
hope you understand !
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