solve this numerical it's answers are 28grams and 22.4litres
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as you know molar mass of calcium nitrate is 164 gms and taken is 82 gms ... that means half moles.
in the equation given we can clearly see that stoichiometric coefficient of CaO is equal to that of calcium nitrate and NO2 is twice of that.
thus half mole of Cao and 1 mole of No2 will be produced hence 28 gms CaO and at STP 22.4 lts of any gas having 1 mole is produced.
in the equation given we can clearly see that stoichiometric coefficient of CaO is equal to that of calcium nitrate and NO2 is twice of that.
thus half mole of Cao and 1 mole of No2 will be produced hence 28 gms CaO and at STP 22.4 lts of any gas having 1 mole is produced.
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