Question

Solve this numerical step by step. I will mark brainliest

Answer 1

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A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.

here, initial velocity , u = 0
time taken , t = 2 sec
distance covered , s = 4m

use formula , S = ut + 1/2 at²
4 = 0 + 1/2 × a × 2²
4 = 2a => a = 2 m/s²

we know, from Newton's 2nd law of motion,
F = ma
here, m = 0.5kg and a = 2m/s²
so, F = 0.5 × 2 = 1N

hence, force applied 1N

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Answer 2

Mass(m)=500g

initial velocity(u)=0m/s

time=2sec

final velocity(v) =displacement /time

v=4/2=2m/s

acceleration(a) = rate of change of velocity

a=2-0/2

a=1ms^-2

force=m×a

f=500×1

f=500gm.m.s^-2