solve this of chapter electrostatics
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Tcos∅ = mg { vertical tension component balance with weight ---(1)
Tsin∅ = KQ²/x² = Q²/4π€x² { horizontal tension component balance with electrostatics force } ------(2)
now, divide (2) by (1)
Tsin∅/Tcos∅ = Q²/4π€x²/mg
tan∅ = Q²/4π€x²mg
now,
T = mg/cos∅ = KQ²/x²sin∅
T= KQ²/x² sin∅ we take
sin∅ = x/L
now,
T = KQ²/x².x/L = Q²L/4π€x³
Tsin∅ = KQ²/x² = Q²/4π€x² { horizontal tension component balance with electrostatics force } ------(2)
now, divide (2) by (1)
Tsin∅/Tcos∅ = Q²/4π€x²/mg
tan∅ = Q²/4π€x²mg
now,
T = mg/cos∅ = KQ²/x²sin∅
T= KQ²/x² sin∅ we take
sin∅ = x/L
now,
T = KQ²/x².x/L = Q²L/4π€x³
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