Question

Solve this of you can :-

A cyclist move A to B with the speed V1 and returns back on the same track with speed V2.

Calculate average speed and average velocity

V1 = 40km/hr
V2= 60km/hr

CHALLENGE

Answer 1

HELLO DEAR,


equal distances are covered at 60 kmph and 40 kmph,

we can use the formula

average speed = (2v1v2)/(v1 + v2)


=> (2×40×60)/(40 + 60)


=> (4800)/100


=> 48kmph


explaination,


Let the distance to one side = x
Total distance = 2x 


time taken for the forward journey = x/40



Time taken for the return journey = x/60


NOW,


total time = x/60 + x/40 = 100x/2400 = x/24


NOW,

average speed = total distance / total time

average speed = 2x/(x/24)

=> 48kmph