solve this on notebook with full explanation....
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= (-√3+√-2)(2√3-i)
= (-√3+i√2)(2√3-i)
= -2×3 +i√3 + i2√6 -(i)²√2.
= -6 + i√3 + i2√6 +√2
= -6 + i(√3+2√6) +√2
= √2-6 + i(√3+2√6)
= (-√3+i√2)(2√3-i)
= -2×3 +i√3 + i2√6 -(i)²√2.
= -6 + i√3 + i2√6 +√2
= -6 + i(√3+2√6) +√2
= √2-6 + i(√3+2√6)
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