Question

solve this one.......... ​

Answer 1

hope it is helpful to you

Answer 2

In ∆ABC, right angled at A

tanC =√3

tan C = opposite side/adjacent side

Let x be the hypotenuse

By applying the Pythagoras Theorem, we get,

BC²=BA²+AC²

x²= √3+ 1²

x²=∆

=>x=2

at angle B sinB =AC/BC =1/2

cosB= √3/2

at angleC sin =√3/2

cosC=1/2

on substitution we get,

1/2×1/2+√3/2×√3/2

=>1/4×√3/4 ×(√3)

= √3×√3+1/4

=3+1/4

=4/4

=1