solve this one also please
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1. Since ABCD is a square.
=) Angle ADC = Angle BCD = 90° ..1.
Since DCE is an equilateral triangle.
=) Angle CDE = Angle DCE = 60° ..2.
Add eq 1 and 2.
=) Angle ADE = Angle BCE = 90°+60°
= 150°.
2. In triangle ADE and triangle BCE:
AD = BC
Angle ADE = Angle BCE
DE = CE
By SAS rule both triangles are congruent.
3. Since triangle ADE is congruent to triangle BCE.
=) AE = BE by cpct.
Hope it's helpful to u.
=) Angle ADC = Angle BCD = 90° ..1.
Since DCE is an equilateral triangle.
=) Angle CDE = Angle DCE = 60° ..2.
Add eq 1 and 2.
=) Angle ADE = Angle BCE = 90°+60°
= 150°.
2. In triangle ADE and triangle BCE:
AD = BC
Angle ADE = Angle BCE
DE = CE
By SAS rule both triangles are congruent.
3. Since triangle ADE is congruent to triangle BCE.
=) AE = BE by cpct.
Hope it's helpful to u.
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