Question

Solve this one...

Evaluate sin ( 45 - theta ) - cos ( 45- theta )​

Answer 1

$\Huge\bf\maltese{\underline{\green{Answer°᭄}}}\maltese$

$\implies$$\large\bf{\underline{\red{VERIFIED✔}}}$

$we \: know \: that \\ = > \sin(90 - \theta) = \cos\theta \\ so \\ = > \sin( {45}^{0} + \theta) \\ = > \cos(90 - (4 {5}^{0} + \theta) \\ = > \cos( {45}^{0} - \theta ) \\ therefore \\ = > \sin( {45}^{0} + \theta) - \cos( {45}^{0} - \theta ) \\= > \cos( {45}^{0} + \theta) - \cos( {45}^{0} - \theta ) \\ = > 0$

$\boxed{I \:Hope\: it's \:Helpful}$

||> - By Dinu <||

Answer 2

Answer:

weknowthat

=>sin(90−θ)=cosθ

so

=>sin(45

0

+θ)

=>cos(90−(45

0

+θ)

=>cos(45

0

−θ)

therefore

=>sin(45

0

+θ)−cos(45

0

−θ)

=>cos(45

0

+θ)−cos(45

0

−θ)

=>0