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Given and wht we have to prove??
in fig 6.18 if lm = cb and LN = CD prove that the AM / AB = AN / AD
hay please mark me brilliant
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where is the question to solve.i understood it is from similar triangles
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Sol.
In ΔABC , we have
LM || CB [Given]
Therefore by Proportionality Theorem, we have
AMAB=ALAC
In ΔACD, we have
LN || CD [Given]
Therefore By Basic Proportionality Theorem, we have
ALAC=ANAD .............. (2)
From (1) and (2), we obtain that
AMAB=ANAD
I hope it will help.
In ΔABC , we have
LM || CB [Given]
Therefore by Proportionality Theorem, we have
AMAB=ALAC
In ΔACD, we have
LN || CD [Given]
Therefore By Basic Proportionality Theorem, we have
ALAC=ANAD .............. (2)
From (1) and (2), we obtain that
AMAB=ANAD
I hope it will help.
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