Question

solve this one please​

Answer 1

Answer:

Given - AE II BD

angle EAB=ABD(ALTERNATE ANGLES)

Now EAB=ABD

SO half of EAB=HALF OF ABD

AND AF BISECTS EAB AND BC BISECTS ABD

SO. ANGLE FAB=ABC

WHICH MAKES A PAIR OF ALTERNATE ANGLES

SO AF II BC...