Math, asked by rujutamumbarkar19, 1 year ago

solve this one pls ​

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Answered by Varshachauhan123
1

So, here it is..

[(√5-2)/(√5+2)]-[(√5+2)/(√5-2)]

=[(√5-2)/(√5+2)*(√5-2)/(√5-2)]-[(√5+2)/(√5-2)*(√5+2)/(√5+2)]

multiplied (√5+2) & (√5-2) both sides

=[(√5-2)²/5-4]-[(√5+2)²/5-4]

=[5-4√5+4]-[5+4√5+4]

=5-4√5+4-5-4√5-4

=-8√5

Hope it helped. ^_^

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Answered by sakshi7860
1

 (\sqrt{5} )^{2}  - 2^{2}  \\ identity \: ( {a}^{2}  -  {b}^{2} ) = (a + b)(a - b) \\  \\ ( \sqrt{5 }  - 2) ^{2}  \\ identity \: (a - b)^{2}  =  {a}^{2}  +  {b}^{2}  - 2ab \\ now \frac{5 + 4 - 2 \sqrt{5}  \times 2}{5 - 4}  \\  =  \frac{9 - 4 \sqrt{5} }{1}  \\  = 9 - 4 \sqrt{5}

ur rationalise is wrong......u have to take both sign negative....bcz denominator is positive

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