solve this one the circled one
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=t^2/(4*4)
=t^2/16
velocity=dy/dt=2t/16=t/8 at t=4
velocity = 4/8=1/2 m/s
=t^2/16
velocity=dy/dt=2t/16=t/8 at t=4
velocity = 4/8=1/2 m/s
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since it relation between position
we have to differenciate
answer is an attachment
we have to differenciate
answer is an attachment
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