Question

Solve this out guys...​

Answer 1

Answer:

(i) A ∩ B = {0, 6, 12}

(ii) A - B = {... ... -18, -12, -6, 18, 24, 30}

Step-by-step explanation:

A = { ... ... ... -18, -12, -6, 0, 6, 12, 18, 24, 30}

As for 'A' x = 6n with n as integers

Substituting n with integers we get the set

But it is mentioned that x value should be less than or equal to 30

So, Set A completes at 30

Now,

B = {0, 2, 6, 12, 20, 30}

As for 'B' x = n(n+1) with n as whole numbers

Substituting n from 0 to 5

We get that set B

${\underline {\underline {\mathbb {TO \ FIND :}}}}$

(i) A ∩ B

(ii) A - B

$\underline {\text {S}\mathfrak {olution : }}$

(i) A ∩ B = {0, 6, 12}

(ii) A - B

A - B  means to remove all the elements of B from A

=> so, A - B = {... ... -18, -12, -6, 18, 24, 30}

Hope it helps

Please mark as brainliest