Question

solve this pair of linear equation by substitution method 2x+3y=13, 4x+5y=23

Answer 1

Hey,
2x+3y=13 -> equation 1
4x+5y=23 -> equation 2

So,in equation 1,
2x+3y=13
2x=13-3y
x=13-2y/2

Now, substitute X's value in equation 2,
4(13-3y/2)-5y=23
2(13-3y)+5y=23
26-6y+5y=23
y=3

And, x= 13-3y/2
=13-3*3/2
=4/2
=2.
So, x=2 and y=3.

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Answer 2

Answer:

=> The value of x = 2, and y = 3.

Step-by-step explanation:

Given equations

$2x+3y=13$   $...(i)$

$4x+5y=23$   $...(ii)$

As we have to solve the linear equation:

By using substitution method:

From equation ( 1 ),

$=> 2x+3y=13$

$y = \frac{13-2x}{3}$

Substitute the value of y in equation ( 2 ):

=> $4x+5y=23$

Now, simplifying it further:

=> $12x+65-10x=69$

=> $2x=69-65$

Subtract the numbers,

=> $2x=4$

By performing division,

=> $x= 2$

Now, substitute the value of x as 2 in the equation ( 1 ) we get,

$=> 2(2)+3y=13$

=> 4 + 3y = 13

=> 3y = 13 - 4

=> 3y = 9

=> y = 3

Hence, the value of x is 2 and y is 3.