solve this pair of linear equation by substitution method 3x-y =3 and 9x - 3y =9 please answer this question
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Answer:
x = 1
y=0
Step-by-step explanation:
3x-y=3 equation 1
9x-3y=9 equation 2
Now, taking value of x in terms of y
so from 1st equation,
3x = 3+y
x = (3+y)/3
Now , putting value of x in equation 2
9[(3+y)/3] -3y = 9
9+3y-3y = 9
0y = 0
y = 0
so, x = (3+y)/3
= (3+0)/3
= 3/3
= 1
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