Question

Solve this paper if you able​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answers:

1. SSA (SAS is a criteria)

2. SAS

3. Median

4. Isosceles

5. EDF

6. True

7. (i) AB = CB (given)

       AD = CD (given)

       BD = BD (common)

   (ii) AB = CB

        AD = CD

        BD = BD

∴ ΔABD ≅ ΔCBD (SSS congruence rule)

  (iii) Since ΔABD ≅ ΔCBD

         By CPCT, ≤ABD ≅ ≤CBD

∴Thus, BD divides ≤ABC into two parts

= BD bisects ≤ABC.

Thanks for the question paper, cause I'm also revising this chapter, so this was a great opportunity (o゜▽゜)o☆