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★ Answer :
The iron oxide has 69.9% iron and 30.1% dioxygen by mass.
Thus, 100 g of iron oxide contains 69.9 g iron and 30.1 g dioxygen.
The number of moles of iron present in 100 g of iron oxide are 69.9/55.8 =1.25
The number of moles of dioxygen present in 100 g of iron oxide are 30.1/32 = 0.94
The ratio of the number of oxygen atoms to the number of carbon atoms present in one formula unit of iron oxide is 2 × 0.94/1.25 = 1.5 : 1=3 : 2.
Hence, the formula of the iron oxide is Fe2O3.
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