Math, asked by 1395823, 2 months ago

solve this please: 12÷2(22-34×21+90-98)67÷877-908+97(879-9087+987)89-76=?

Answers

Answered by hluteipach93
0

Answer:

3254 well they are kinda long like really really long

Answered by sanchitwagh460
1

(

12

2

(22−(34)(21)+90−98))(67)

877

−908+97(879−9087+987)(89)−76

=

6(22−(34)(21)+90−98)(67)

877

−908+97(879−9087+987)(89)−76

=

6(22−714+90−98)(67)

877

−908+97(879−9087+987)(89)−76

=

6(−692+90−98)(67)

877

−908+97(879−9087+987)(89)−76

=

6(−602−98)(67)

877

−908+97(879−9087+987)(89)−76

=

(6)(−700)(67)

877

−908+97(879−9087+987)(89)−76

=

(−4200)(67)

877

−908+97(879−9087+987)(89)−76

=

−281400

877

−908+97(879−9087+987)(89)−76

=

−1077716

877

+97(879−9087+987)(89)−76

=

−1077716

877

+97(−8208+987)(89)−76

=

−1077716

877

+(97)(−7221)(89)−76

=

−1077716

877

+(−700437)(89)−76

=

−1077716

877

+−62338893−76

=

−54672286877

877

−76

=

−54672353529

877

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