solve this please...........
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(10ⁿ - 1)
= [(11-1)ⁿ - 1]
As we solve this....
We get,
11²ᵃ⁺¹ - 1 = 11ⁿ - 1
n = even
(c) Even values of n
= [(11-1)ⁿ - 1]
As we solve this....
We get,
11²ᵃ⁺¹ - 1 = 11ⁿ - 1
n = even
(c) Even values of n
student48:
tell with explanation plz
Ok
I have done it
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