Question

solve this please...........​

Answer 1

Answer:

angle ECD=60°

Step-by-step explanation:

Let x be the common factor for the angles of triangle ABC...

=3x+2x+1x=180°...... (angle sum property of triangle)

=6x=180°=x=30°

therefore angle A=3×30=90°,angle B=2×30=60° and angle C=1×30=30°

Now angle ACD=angle CAB+angle ABC(exterior angle property)

angle (ACE+ECD)= 90°+60°[since angle ACD=angle(ACE+ECD)]

90°+angle ECD=150°

angle ECD=60°.

Answer 2

$\large{\boxed{\bf{Answer\ :-}}}$

• The value of ∠ECD is 60°

__________________________

Given :-

• ∠A : ∠B : ∠C = 3 : 2 : 1

To Find :-

• ∠ECD

__________________________

$\large{\boxed{\bf{Solution}}}$

★ Put the value of x in the ratio

• 3x

• 2x

• x

Then,

➪ 3x + 2x + x = 180 [ angle sum property of triangle ]

➪ 6x = 180

➪ x = 180/6

➪ x = 30°

Put the value of x in the ratio :-

• ∠A = 3 × 30 = 90°

• ∠B = 2 × 30 = 60°

• ∠C = x = 30°

Now,

• ∠ACB + ∠ACE + ∠ECD = 180° [ linear pair ]

➪ 30 + 90 + ∠ECD = 180

➪ 120 + ∠ECD = 180

➪ ∠ECD = 180 - 120

➪ ∠ECD = 60°

Hence, the value of ∠ECD is 60° .