Solve this please.....
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x-3=0
x=3
putting value of x in equation x^2-7x+12
(3)^2-7×3+12
9-21+12
-21+21=0
x^2-7x+12 ÷ x-3 we get x-4 as questient and 0 as remainder
x^2-7x+12=x-3 × (x-4)+0
x^2-7x+12=x^2-4x-3x+12
x^2-7x+12=x^2-7x+12
hope it helps please mark it as brainliest answer.............
x=3
putting value of x in equation x^2-7x+12
(3)^2-7×3+12
9-21+12
-21+21=0
x^2-7x+12 ÷ x-3 we get x-4 as questient and 0 as remainder
x^2-7x+12=x-3 × (x-4)+0
x^2-7x+12=x^2-4x-3x+12
x^2-7x+12=x^2-7x+12
hope it helps please mark it as brainliest answer.............
Namit1111:
pls mark it as brainliest answer
Answered by
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This is correct answer.
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