Question

Solve this please...

Answer 1

the point of intersection of the above lines can be found by applying substitution method To these equations.

x+2y=7
x=7-2y
substitute in the 2nd eqn.
x-y=4
7-2y-y=4
3=3y
y=1
subs y=1 in 1st eqn
x=7-2y
x=7-2(1)
x=5
therefore pt. of intersection is (5,1)
the eqn. of the line passing thro' origin (0,0) and (5,1) is
y-0/1-0 =x-0/5-0
y/1=x/5
x-5y=0