Question

Solve this please ......​

Answer 1

${\bold{\red{\huge{Your\:Solution}}}}$

$Rate\:of\:Diffusion$  ∝  $\frac{1}{Molar\:weight\:of\:gas}$

$Let\:Distance\:Covered\:by\:X\:is\:d\:then\:distance\:covered\:by\:Y\:is\:24-d$

$If\:r_{x}\:and\:r_{y}\:are\:the\:rate\:of\:diffusion\:of\:gases\:X\:and\:Y$

$\frac{rx}{ry}=\frac{d}{24-d}  =\sqrt[]{\frac{40}{10} } =2$

[∵$Rate\:of\:Diffusion$ ∝ $Distance\:Travelled$ ]

$d=48-2d$

$3d=48$

$d=16cm$

Hence,(c) is the Correct Answer.

Answer 2

$\textbf{Answer is in Attachment !}$