Question

Solve this please and fast​

Answer 1

The answer will Bes 3x/2

Answer 2

Answer:

$\frac{3 {x}^{2}y }{2xy} \\ = \frac{3 {(x)}^{2 - 1}{(y)}^{1 - 1} }{2} \\ = \frac{3 {x}^{1} {y}^{0} }{2} \\ = \frac{3x \times 1}{2} \\ = \frac{3x}{2} \\ \large{ \boxed{= \underline{ \underline{ \frac{3}{2} x}}}} \\ \\ \large {\underline{Note} : } \\ * \: \: \: \frac{ {a}^{3} }{ {a}^{2} } = {(a)}^{3 - 2} = {a}^{1} = a \\ * \: \: \: a^0 = 1$