Question

SOLVE THIS PLEASE AND GIVE ME FULL EXPLANATION

A crystal is made up of metal ions 'M1' and 'M2' and oxide ions. Oxide ions form a ccp lattice structure. The cation 'M1 'occupies 50% of octahedral voids and the cation "M2' occupies 12.5% of tetrahedral voids of oxide lattice. The oxidation numbers of 'M1' and 'M2' are,respectively :
1) +2, +4
2) +3, +1
3) +1, +3
4) +4, +2.​

Answer 1

Answer:

option 1) +2 , +4

Explanation:

• Effective number of atoms in CCP is 4

since the oxide ions are the ones forming CCP,

no. of oxide ions = 4

• total octahedral voids in a CCP lattice = 4 and tetrahedral voids are double the amount of octahedral voids.

hence,

number of octahedral voids = 4

number of tetrahedral voids = 8

Given that,

• M1 occupies 50%(1/ 2) of O- voids

number of M1 atoms = 1/ 2 × 4

number of M1 atoms = 1/ 2 × 4= 2

• M2 occupies 12.5%(1/ 8) of T - voids

number of M2 atoms = 1/ 8 × 8

number of M2 atoms = 1/ 8 × 8 = 1

Hence, formula of the compound

= (M1)² (M2) O⁴

now, this crystal is neutral and the oxidation state of Oxide ions is -2

hence

• hence M1 oxidation state = 2+
• hence M1 oxidation state = 2+M2 oxidation state = 4+

that is option 1.

______________________

$\mathfrak{hope \: this \: helps }$

just wanted to let you know that capacitance in parallel get added the same way they're added when resistances are in series. (u getting my point ?)

so your answer was a bit different from the actual answer but I'm glad you tried to help :)

$\mathfrak{thank \: you \: }$