Math, asked by jheelnanda, 1 year ago

solve this please asap..!!

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Answered by deepak0916
0
3rd term + 4th term = 14
a+d+a+2d=14
2a+3d=14---------(i)
a-d + a + a+d + a+2d= 12
2a+2d=12
a+d=6--------------(ii)
from eq i and ii
2(6-d)+3d=14
12-2d+3d=14
d= 2
putting the value of d in eq ii
a+2 =6
a=4
AP is(4-2), (4), (4+2), (4+4)
=2,4,6,8
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