solve this please .....BCB
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s=200
ap series=20,19,18
d=19-20=-1
a=20
an=?
n=?
an=a+(n-1)d
sn=n/2(2a+(n-1)d)
200=n/2(2*20+(n-1)-1)
200=n/2(40 -1n+1)
400=n(39-n)
400=39n-n square
now u can solve this equation and then u get the value of n and u can find an by the formula
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