Question

solve this please fast​

Answer 1

ii)

yes ,∆ABD=~∆CBD

in ∆ABD and∆CBD

AD=CD (given)

AB=CB(given)

BD =BD (coman)

by SSS Crite area

∆ABD=~∆CBD

iii)

yes BD bisect the /_ABC

by above congruent rule

angle ABD and angle CBD are equal

and both angle from the lineBD are equal

hence it is bisector