solve this please find P-> and Q->
Attachments:
Answers
Answered by
3
P = 2i +2j + k
Q = i - j +2k
Now,
P.Q = (2i +2j + k).(i - j +2k)
=>2i(i - j +2k)+2j(i - j +2k)+k(i - j +2k)
=>2 -0 +0 +0 -2+0+0+0+2
=>2
{because we know,
i.i = 1
j.j = 1
k.k = 1 and any other mixed is 0}
So,
P.Q = 2
Cheers!
Similar questions