Question

solve this please find P-> and Q->​

Answer 1

P = 2i +2j + k

Q = i - j +2k

Now,

P.Q = (2i +2j + k).(i - j +2k)

=>2i(i - j +2k)+2j(i - j +2k)+k(i - j +2k)

=>2 -0 +0 +0 -2+0+0+0+2

=>2

{because we know,

i.i = 1

j.j = 1

k.k = 1 and any other mixed is 0}

So,

P.Q = 2

Cheers!