Question

Solve this ;-

Please give correct ans....

Answer 1

HELLO DEAR,

given that:-

<B=50°,<D=90°

and <C=30°

In ∆ABC

=> <A+<B+<C=180°

=> <A=180° - 50 -30

=> <A=180°-80°

=> <A=100°


AE IS A bisector of <A

hence,

< BAE = < CAE------(1)

and ,

<BAE + < CAE = < BAC

=> 2<BAE =100° ---FROM (1)

=> <BAE=50°/2

=> <BAE=50°


in ∆ABE

<AEB + <BAE + < ABE= 180°

=> <AEB +50°+ 50° =180°

=> <AEB =180°-100°

=> <AEB = 80°


in ∆ADE

<ADE + <DAE + < AED =180°

=> 90° +<DAE +80°=180°

=> <DAE =180° -170°

=> <DAE =10° = X



I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

hope it helps u .....................