Question

solve this please Guys ......

Answer 1

HELLO DEAR,


$\frac{ {4}^{5} + {4}^{5} + {4}^{5} + {4}^{5} }{ {3}^{5} + {3}^{5} + {3}^{5} } . \frac{ {6}^{5} + {6}^{5} + {6}^{5} + {6}^{5} + {6}^{5} + {6}^{5} }{ {2}^{5} + {2}^{5} } = {2}^{n} \\ \\ \\ = > \frac{ {4}^{5}(1 + 1 + 1 + 1 ) }{ {3}^{5} (1 + 1 + 1)} . \frac{ {6}^{5}(1 + 1 + 1 + 1 + 1 + 1) }{ {2}^{5} (1 + 1 )} = {2}^{n} \\ \\ \\ = > \frac{4 \times {4}^{5} }{3 \times {3}^{5} } . \frac{6 \times {6}^{5} }{2 \times {2}^{5} } = {2}^{n} \\ \\ \\ = > \frac{4 \times {( {2}^{2}) }^{5} }{ {3}^{5} } . \frac{ {(3 \times 2)}^{5} }{ {2}^{5} } = {2}^{n} \\ \\ \\ = > \frac{4 \times {2}^{10} }{ {2}^{5} } . \frac{ {3}^{5} \times {2}^{5} }{ {3}^{5} } = {2}^{n} \\ \\ \\ = > {2}^{2} \times {2}^{10} = {2}^{n} \\ \\ \\ = > {2}^{10 + 2} = {2}^{n} \\ \\ \\ = > n = 12$



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THANKS