Question

solve this please heplp

Answer 1

Hello Mate!

$\frac{1}{3 - \sqrt{8} } \times \frac{3 + \sqrt{8} }{3 + \sqrt{8} } \\ \frac{3 + \sqrt{8} }{9 - 8} = 3 + \sqrt{8} \\ \frac{1}{ \sqrt{8 } - \sqrt{7} } \times \frac{ \sqrt{8} + \sqrt{7} }{ \sqrt{8} + \sqrt{7} } \\ \frac{ \sqrt{8} + \sqrt{7} }{8 - 7} = \sqrt{8} + \sqrt{7} \\ \frac{1}{ \sqrt{7} - \sqrt{6} } \times \frac{ \sqrt{7} + \sqrt{6} }{ \sqrt{7} + \sqrt{6} } \\ \frac{ \sqrt{7} + \sqrt{6} }{7 - 6} = \sqrt{7} + \sqrt{6} \\ \frac{1}{ \sqrt{6} - \sqrt{5} } \times \frac{ \sqrt{6} + \sqrt{5} }{ \sqrt{6} + \sqrt{5} } \\ \frac{ \sqrt{6} + \sqrt{5} }{1} = \sqrt{6} + \sqrt{5} \\ \frac{1}{ \sqrt{5} - 2 } \times \frac{ \sqrt{5} + 2} { \sqrt{5} + 2 } \\ \frac{ \sqrt{5} + 2}{5 - 4} = \sqrt{5} + 2 \\ 3 + \sqrt{8} - ( \sqrt{8} + \sqrt{7} ) + ( \sqrt{7} + \sqrt{6} ) - ( \sqrt{6} + \sqrt{5} ) + ( \sqrt{5} + 2) \\ 3 + \sqrt{8} - \sqrt{8} - \sqrt{7} + \sqrt{7} + \sqrt{6 } - \sqrt{6} - \sqrt{5} + \sqrt{5} + 2 \\ 3 + 2 = 5$

Hope it helps☺!

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