Question

solve this.... please
it's really important....​

Answer 1

Given

diameter of the silver =0.7mm=7×10^-4m

radius of the wire(r)=3.5×10^-4m

Area of cross section (A)=3.85×10^-7m^2

resistivity (p)=1.6×10^-8 ohm-m

resistance (R)=1ohm

R=pl/A

1=1.6×10^-8×l/3.85×10^-7

l=3.85×10^-7/1.6×10^-8

l=24.0625m

so length of wire=24.0625m