Question

Solve this please, last digit in
${152}^{99}$

Answer 1

Multiples of 2 in terms of power:
2
4
8
16
32
Now this is the order of the last digit of each of the multiples:-
2-power 1
4- power 2
8- power 3
6- power 4
.
So divide 99 by 4: You get 3 as remainder.
And the last digit corresponding to 3 is 8.
Hence 8 is the answer.