solve this please...need help
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T1 = 327°C = 327+273 K = 600K
RMS1 = √(3RT1)/M
Now,
RMS2 = RMS1/2 (Given)
equating both sides, we get
√(3RT2)/M = √(3RT1)/2M
√T2 = √T1/2
2√T2 = √T1
squaring both sides,
4×T2=T1
T2=600/4=150K
150K = 150°C-273°C = -123°C
So, Answer is -123° C
RMS1 = √(3RT1)/M
Now,
RMS2 = RMS1/2 (Given)
equating both sides, we get
√(3RT2)/M = √(3RT1)/2M
√T2 = √T1/2
2√T2 = √T1
squaring both sides,
4×T2=T1
T2=600/4=150K
150K = 150°C-273°C = -123°C
So, Answer is -123° C
Anonymous:
thanks again!
welcome again!
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