Math, asked by Anonymous, 1 year ago

solve this please
thank you.

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Answered by siddhartharao77
2
Given: 4 \sqrt{3} x^2 + 5x - 2 \sqrt{3} = 0

4 \sqrt{3} x^2 + 8x - 3x - 2 \sqrt{3} = 0

4x( \sqrt{3}x + 2) -  \sqrt{3} ( \sqrt{3} x + 2) = 0

(4x -  \sqrt{3} )( \sqrt{3} x + 2) = 0

x =  \frac{ \sqrt{3} }{4} ,  \frac{-2}{ \sqrt{3} }


Hope this helps!

siddhartharao77: :-)
Answered by Anonymous
1
Hi,

Please see the attached file!


Thanks
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