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Given that areas of circle and square are equal.
If a is the side of a square, then the area of the square is a2 sq units.
If r is the radius of a circle, then the area of the circle is πr2 sq units.
According to the condition,
a2 = πr2
a = r√π
The perimeter of a square is 4a.
The perimeter of a circle is 2πr.
Thus the ratio of the perimeter of a square and a circle is
= 4a / 2πr = 2r√π / πr [ a = r√π]
= 2 / √π
Thus, the ratio is 2 / √π.
that areas of circle and square are equal.
If a is the side of a square, then the area of the square is a2 sq units.
If r is the radius of a circle, then the area of the circle is πr2 sq units.
According to the condition,
a2 = πr2
a = r√π
The perimeter of a square is 4a.
The perimeter of a circle is 2πr.
Thus the ratio of the perimeter of a square and a circle is
= 4a / 2πr = 2r√π / πr [ a = r√π]
= 2 / √π
Thus, the ratio is 2 / √π.
If a is the side of a square, then the area of the square is a2 sq units.
If r is the radius of a circle, then the area of the circle is πr2 sq units.
According to the condition,
a2 = πr2
a = r√π
The perimeter of a square is 4a.
The perimeter of a circle is 2πr.
Thus the ratio of the perimeter of a square and a circle is
= 4a / 2πr = 2r√π / πr [ a = r√π]
= 2 / √π
Thus, the ratio is 2 / √π.
that areas of circle and square are equal.
If a is the side of a square, then the area of the square is a2 sq units.
If r is the radius of a circle, then the area of the circle is πr2 sq units.
According to the condition,
a2 = πr2
a = r√π
The perimeter of a square is 4a.
The perimeter of a circle is 2πr.
Thus the ratio of the perimeter of a square and a circle is
= 4a / 2πr = 2r√π / πr [ a = r√π]
= 2 / √π
Thus, the ratio is 2 / √π.
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