solve this please urgent
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yaa
Let us assume that 3 + √5 is a rational number.
Now,
3 + √5 = a/b
[Here a and b are co-prime numbers, where b ≠ 0]
√5 = a/b - 3
√5 = (a - 3b)/b
Here, {(a - 3b)/b} is a rational number.
But we know that √5 is an irrational number.
So, {(a - 3b)/b} should also be an irrational number.
Hence, it is a contradiction to our assumption.
Thus, 3 + √5 is an irrational number.
Hence proved, 3 + √5 is an irrational number.
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