Question

Solve this please very IMP
with steps ​

Answer 1

Step-by-step explanation:

We know that in a cyclic quadrilateral

exterior angle is equal to the interior opposite angle

. It can be written as

Exterior ∠EDC = ∠A

Exterior ∠DCE = ∠B

We know that AB || CD

So we get ∠EDC = ∠B and ∠DCE = ∠A

We get ∠A = ∠B Therefore,

it is proved that △ AEB is isosceles.