Math, asked by shivansh6738, 1 year ago

solve this pleaseeeeeeeeeeee

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seemasssingh4p893y4: are u Shivansh Dubey from sln

raushan6198: no

seemasssingh4p893y4: I m not asking from u

raushan6198: shut up

seemasssingh4p893y4: u just shut up

Answers

Answered by raushan6198

log

$log_{ {3}^{2} }(x) + log_{3}(x) = 3 \\ \frac{1}{3 } log_{3}(x ) = log_{3}( {3}^{3} ) - log_{3}(x) \\ log_{3}( {x}^{ \frac{1}{3} } ) = log_{3}( \frac{27}{x} ) \\ {x}^{ \frac{1}{3} } = \frac{27}{x} \\ {x}^{ \frac{3}{4 } } = {3}^{3} \\ x = {3}^{4 } \\ x = 81$

hope it will help you

raushan6198: what is your answer

shivansh6738: if I would have known I wouldn't had asked

raushan6198: answer always be 81 ok

raushan6198: don't make contradiction

shivansh6738: shut up your answer is not in option and when you are wrong you are not accepting it!you are egoistic

raushan6198: first of all learn how should speak to other bro?

shivansh6738: first you must know how to solve logarithms

raushan6198: don't try to be oversmart

shivansh6738: I am sorry for the rude language but dude your answer is wrong

raushan6198: let my questions is wrong ok

Answered by riyanshi02

log

\begin{lgathered}log_{ {3}^{2} }(x) + log_{3}(x) = 3 \\ \frac{1}{3 } log_{3}(x ) = log_{3}( {3}^{3} ) - log_{3}(x) \\ log_{3}( {x}^{ \frac{1}{3} } ) = log_{3}( \frac{27}{x} ) \\ {x}^{ \frac{1}{3} } = \frac{27}{x} \\ {x}^{ \frac{3}{4 } } = {3}^{3} \\ x = {3}^{4 } \\ x = 81\end{lgathered}log32(x)+log3(x)=331log3(x)=log3(33)−log3(x)log3(x31)=log3(x27)x31=x27x43=33x=34x=81

hope it will help you

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solve this pleaseeeeeeeeeeee