Question

solve this...
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Answer 1

Answer:

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Answer 2

Let Ankur be represented as A, Syed as S and David as D.

The boys are sitting at an equal distance.

Hence, △ASD is an equilateral triangle.

Let the radius of the circular park be r meters.

∴OS=r=20m.

Let the length of each side of △ASD be x meters.

Draw AB⊥SD

∴SB=BD= ½ SD= x/2 m

In △ABS,∠B=90°

By Pythagoras theorem,

AS²=AB²+BS²

∴AB²=AS² −BS² =x²−(x/2)² = 3x²/4

∴AB= √3x/2 m

Now, AB=AO+OB

OB=AB−AO

OB=(√3x/2−20) m

In △OBS,

OS² =OB² +SB²

20² =(√3x/2-20)²+(x/2)²

400= ¾x²+400−2(20)(√3x/2)+ x²/4

0=x²−20√3x

∴x=20√3m

The length of the string of each phone is

20√3m.

Step-by-step explanation:

Hope this answer will be helpful!!