Chemistry, asked by AadyaAgarwalCMS, 9 months ago

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Answered by Mihir1001

$\huge{\underline{\mathfrak{\textcolor{blue}{Answer :}}}}$

$\huge\boxed{\fcolorbox{pink}{pink}{N( 35percent ) and O( 60percent )}}$

$\huge{\underline{\mathrm{\textcolor{red}{Step-by-step \: \: explanation :}}}}$

$\LARGE{\underline{\mathtt{\textcolor{violet}{Given :-}}}}$

$\large{NH_4NO_3}$

$\LARGE{\underline{\mathtt{\textcolor{green}{To \: \: find :-}}}}$

$\LARGE{\underline{\mathtt{\textcolor{teal}{Concept \: \: used :-}}}}$

Mole Concept

$\LARGE{\underline{\mathtt{\textcolor{blue}{Solution :-}}}}$

We have,

N = 14 units
H = 1 unit
O = 16 units

In the given formula $\large{NH_4NO_3}$ ,

no. of nitrogen atoms = 2
no. of hydrogen atoms = 4
no. of oxygen atoms = 3

Molecular mass of $\large{NH_4NO_3}$

= 2( mass of Nitrogen ) + 4( mass of Hydrogen ) + 3( mass of Oxygen )

= 2( 14 units ) + 4( 1 unit ) + 3( 16 units )

= 28 units + 4 units + 48 units

= ( 28 + 4 + 48 ) units

= 80 units

Now,

$<hr>$

mass of N in the formula

= 2( mass of nitrogen )

= 2( 14 units )

= 28 units

Hence,

mass percentage of N in $\bold{NH_4NO_3}$

$\Large{ = \left[ \frac{mass \: of \: N}{mass \: of \: NH_4NO_3} \times 100 \right] }$ %

$\Large{ = \left[ \frac{28 \: units }{80 \: units } \times 100 \right] }$ %

$\Large{ = \left[ \frac{28 \: \cancel{units} }{8 \cancel{0} \: \cancel{units} } \times 10 \cancel{0} \right] }$ %

$\Large{ = \left[ \frac{28 }{_4 \cancel{8} } \times \cancel{10} {}^{5} \right] }$ %

$\Large{ = \left[ \frac{ {}^{7} \: \cancel{28} }{_1 \: \cancel{4} } \times 5 \right] }$ %

$\Large{ = \left[ 7 \times 5 \right] }$ %

$\Large{ = 35}$ %

$<hr>$

mass of O in the formula

= 3( mass of oxygen )

= 3( 16 units )

= 48 units

Hence,

mass percentage of O in $\bold{NH_4NO_3}$

$\Large{ = \left[ \frac{mass \: of \: O}{mass \: of \: NH_4NO_3} \times 100 \right] }$ %

$\Large{ = \left[ \frac{48 \: units }{80 \: units } \times 100 \right] }$ %

$\Large{ = \left[ \frac{48 \: \cancel{units} }{8 \cancel{0} \: \cancel{units} } \times 10 \cancel{0} \right] }$ %

$\Large{ = \left[ \frac{48 }{_4 \cancel{8} } \times \cancel{10} {}^{5} \right] }$ %

$\Large{ = \left[ \frac{ {}^{12} \: \cancel{48} }{_1 \: \cancel{4} } \times 5 \right] }$ %

$\Large{ = \left[ 12 \times 5 \right] }$ %

$\Large{ = 60}$ %

$<hr>$

$\LARGE{\underline{\mathtt{\textcolor{magenta}{Conclusion :-}}}}$

mass % of nitrogen ( N ) = 35 %
mass % of oxygen ( O ) = 60 %

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Answered by shankarporika76

Answer:

N% IS 35, O% is 60 H% is 5%

Explanation:

NH4NO3 molecular wt is 80

% of N is (2)(14)(100)÷80 = 35

% of O is (3)(16)(100)÷80 = 60

100-(35+60) = % of hydrogen

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