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5th one....in a paper then send it....plz
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ax +by +c =0 ⇒ t² +0 -15
here a= 1 ,b = 0 , c = -15 ,
t² - 15 = (t+√15) (t-√15)
x⇒t+√15=0 or x⇒t-√15 =0
t= -√15 t = √15
α = -√15 β= √15
we know α +β =-b/a
and α × β =c/a
therefore α +β = -√15 + √ 15 =0
-b/a = - 0/ 1 = 0
and also α × β =√15 × -√15 = -15
c / a = -15/1 = -15
therefore α +β = - b/a and α × β =c/a
here a= 1 ,b = 0 , c = -15 ,
t² - 15 = (t+√15) (t-√15)
x⇒t+√15=0 or x⇒t-√15 =0
t= -√15 t = √15
α = -√15 β= √15
we know α +β =-b/a
and α × β =c/a
therefore α +β = -√15 + √ 15 =0
-b/a = - 0/ 1 = 0
and also α × β =√15 × -√15 = -15
c / a = -15/1 = -15
therefore α +β = - b/a and α × β =c/a
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