solve this plz.........
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hope it will help you
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kavita1159:
thanks so much
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expand line AB towards DE which intersect DC at f.
angleCBF =180-110
=70°
angle DFB=angle FDE=120° alternate angles
angle BFC=180-120
=60°
60+70+angle C = 180 angle sum property of triangle
angle C=180-130
=50°
so the angle BCD= 50°
angleCBF =180-110
=70°
angle DFB=angle FDE=120° alternate angles
angle BFC=180-120
=60°
60+70+angle C = 180 angle sum property of triangle
angle C=180-130
=50°
so the angle BCD= 50°
answer is wrong
50 degree is the answer
sorry its 50°
thanks for informing me
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