Question

solve this plz.......​

Answer 1

yes its ans is 0 or 4

if roots are real abd equal tyen b2 - 4ac =0

so. k2 - 4k=0

then k= 4 or 0

Answer 2

${x}^{2} + kx + k = 0 \\ here \: a = 1 \\ b = k \\ c = k \\ so \: d = {b}^{2} - 4ac \\0 = {k}^{2} - 4 \times 1 \times k \\ 0 = {k}^{2} - 4k \\ 4k = {k}^{2} \\ therefore \: k = 4$