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x=1/3 because (1+2+3)/9= 6/9=2/3 3**2 =9
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when base are same then power is added so
(3)^{1/9+2/9+3/9}= (3)^2x.
[ 3^2=9 so we can write 9^x in (3^2x)
both side base are same so their power will became equal to each other
(1/9+2/9/3/9)=2
taking LCM
(1+2+3)/9 =2x
6/9=2x
2/3=2x. (6/9 is divisible by 3 )
2/2*3 =x
1/3 =x
( 2 is cacle bcoz is present in both numerator and demomerator )
I hope u get it !!
(3)^{1/9+2/9+3/9}= (3)^2x.
[ 3^2=9 so we can write 9^x in (3^2x)
both side base are same so their power will became equal to each other
(1/9+2/9/3/9)=2
taking LCM
(1+2+3)/9 =2x
6/9=2x
2/3=2x. (6/9 is divisible by 3 )
2/2*3 =x
1/3 =x
( 2 is cacle bcoz is present in both numerator and demomerator )
I hope u get it !!
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