Question

solve this plz.. .................. fast fasr

Answer 1

x+y=3
x^2+y^2= 12

Now, (x+y)^2=x2+y2+2xy
3^2= 12 +2xy
9=12 +2xy ,. So xy= -3/2

Answer 2

let first number be X

second number be y

According to the question

x+ y =3

y = 3-x

and

x²+ y²= 12 -----(2)

substitute y in (2)

x²+(3-x)² = 12

x²+9-6x+x²=12

2x²-6x= 12-9

2x²-6x-3=0

let a = 2 b =-6 c=-3

√b²-4ac

√(-6)²-4× 2× -3

√ 35+24

√ 59

-b +√ 59/2× 2. - b -√59/4

6+7.6/4. 6-7.7/4

3.4. -0.4

hence 3.4 is X is -0 .4

substitute X in y

y= 3-3.4

y=- 0.4

y= 3-0.4

2.6