Math, asked by ishitakaul, 1 year ago

solve this plz find 3 vertex

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Answered by kush2735
0

Hi there I am a little bit of a good time to get the same time as I have a great day and I will be a good time to get the same time as I have a great day and I will be a good time to get the same time as I have a great day and I will be a good time to get the same time as I have a great day and I will be a good time to get the same time as I have a great day and I will be a good time to get the same time as I have a great day and I will be a bit too late and the rest are not in my case it would have a nice to hear about it but it's a bit too late and the

Answered by bharat9291
0
AB = √ ( -2-2) ^2 + 0
AB = √16 = 4 units
BC = AC = AB = 2 units
AC = √ (x-2) ^2 + ( y-0 ) ^2
AC =√ x^2 -4x + 4 + y^2 ............( EQ 1)

BC = √ ( X+2) ^2 + (y-0) ^2
BC = √ x^2 + 4x + 4 + y ^2 .........EQ 2
from equation 1 and 2
8 X = 0
X = 0
now AC = 2 units
so√ x^2 -4x + 4 + y ^2 = 4
squaring both sides
x^2 -4 X +4 + y ^2 = 16
put X = 0
y ^2 = 16
y = +- 4
so coordinates may be either ( 0,4) or (0,-4)
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ImArnav: you didnt square -4. ,
bharat9291: where bro
bharat9291: got it
ImArnav: the first step
bharat9291: thanks dude
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